3w^2-4w=319

Solution for 3w^2-4w=319 equation:

3w^2-4w=319

We move all terms to the left:

3w^2-4w-(319)=0

a = 3; b = -4; c = -319;
Δ = b2-4ac
Δ = -42-4·3·(-319)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-62}{2*3}=\frac{-58}{6}
=-9+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+62}{2*3}=\frac{66}{6}
=11
$